0=-16x^2-29x-6

Solution for 0=-16x^2-29x-6 equation:

0=-16x^2-29x-6

We move all terms to the left:

0-(-16x^2-29x-6)=0

We add all the numbers together, and all the variables

-(-16x^2-29x-6)=0

We get rid of parentheses

16x^2+29x+6=0

a = 16; b = 29; c = +6;
Δ = b2-4ac
Δ = 292-4·16·6
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{457}}{2*16}=\frac{-29-\sqrt{457}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{457}}{2*16}=\frac{-29+\sqrt{457}}{32}
$